The body falls from a height of 45 m in what time the body will pass the last meter.

Data: h (height from which the taken body began its fall) = 45 m; h1 (considered height) = 1 m.

Constants: g (acceleration due to gravity) = 9.81 m / s2.

1) Speed at the moment of touching the ground: V = √ (2 * g * h) = √ (2 * 9.81 * 45) = 29.714 m / s.

2) Speed at 44 m: V1 = √ (2 * g * (h – h1)) = √ (2 * 9.81 * (45 – 1)) = 29.382 m / s.

3) Travel time of the last meter: t = (V – V1) / g = (29.714 – 29.382) / 9.81 = 0.03384 s = 33.84 ms.

Answer: The body will pass the last meter in 33.84 ms.