The body falls from a height of h = 1 km with zero initial velocity. Ignoring the air resistance

The body falls from a height of h = 1 km with zero initial velocity. Ignoring the air resistance, determine how long it will take for the body to pass: 1) the first 10 meters of the path; 2) the last 10 meters of the way.

Task data: h (full height) = 1 km = 1000 m; V0 (initial speed) = 0 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The travel time of the first 10 meters of the path: h1 = g * t1 ^ 2/2 and t1 = √ (2h1 / g) = √ (2 * 10/10) = 1.414 s.

2) The total duration of the fall: t = √ (2h / g) = √ (2 * 1000/10) = 14.142 s.

3) The duration of the fall to the last 10 meters of the path: t3 = √ (2 * (h – h2) / g) = √ (2 * (1000 – 10) / 10) = 14.071 s.

4) Travel time of the last 10 meters: t2 = t – t3 = 14.142 – 14.071 = 0.071 s.

Answer: The first 10 meters the body will fly in 1.414 s, and the last 10 meters in 0.071 s.



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