The body falls from a height of h = 19.6 m with an initial velocity v0 = 0. How long does it take

The body falls from a height of h = 19.6 m with an initial velocity v0 = 0. How long does it take for the body to cover the first and last 1 m of its path?

Task data: h (total height) = 19.6 m; V0 (initial speed) = 0 m / s.

Constants: g (acceleration due to gravity) ≈ 9.8 m / s2.

1) The travel time of the first meter of the path: h1 = g * t12 / 2, whence t1 = √ (2h1 / g) = √ (2 * 1 / 9.8) = 0.452 s.

2) Total fall time: t = √ (2h / g) = √ (2 * 19.6 / 9.8) = 2 s.

3) Falling time to the last meter of the way: t3 = √ (2 * (h – h2) / g) = √ (2 * (19, 6 – 1) / 9.8) = 1.948 s.

4) Travel time of the last meter of the path: t2 = t – t3 = 2 – 1.948 = 0.052 s.

Answer: The body will pass the first meter of the path in 0.452 s, and the last one in 0.052 s.