The body falls to the ground from a height of 50 m. How long does it take for it to fly half the way?

Task data: h (total height) = 50 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The duration of the fall during the first half of the journey: h1 = h / 2 = g * t1 ^ 2/2, whence t1 ^ 2 = h * 2 / 2g and t = √ (h / g) = √ (50/10) = 2.24 s.

2) The total duration of the fall: h = g * t ^ 2/2, whence t = √ (2h / g) = 3.16 s.

3) The duration of the fall when passing the second half of the path: t2 = t – t1 = 3.16 – 2.24 = 0.92 s.

Answer: The body flew the first half of the journey in 2.24 s, and the second in 0.92 s.