The body fell from a height of 20m. What will its height be in half the time?

Given:

H = 20 m – the height from which the body falls.

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to find the height of the body h in half the time of the fall.

First, let’s find the total fall time:

t = square root (2 * H / g) = square root (2 * 20/10) = square root (40/10) = square root (4) = 2 s.

Now let us find the path S that the body will fly by in time t / 2:

S = g * t ^ 2/2 ^ 2 * 2 = 10 * 2 * 2/2 * 2 * 2 = 10/2 = 5 m.

Then the body height in time t / 2 will be equal to:

h = H – S = 20 – 5 = 15 meters.

Answer: after half the time of the fall, the height of the body will be 15 meters.