The body freely fell from a height of 54 m. At what height was it when one third of the total time of the fall had passed?

Task data: h0 (initial height) = 54 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) The duration of the entire fall: h0 = g * t ^ 2/2, whence t = √ (2h0 / g) = √ (2 * 54/10) = 3.268 s.

2) Considered fall time: t1 = t / 3 = 3.268 / 3 = 1.09 s.

3) Height after 1/3 of the fall time: h1 = h0 – g * t1 ^ 2/2 = 54 – 10 * 1.09 ^ 2/2 = 48.06 m.

Answer: After 1/3 of the time of the fall, the body will be at a height of 48.06 m.