The body from a state of rest at uniformly accelerated motion with an acceleration of 1 m / s ^ 2 has passed 50 m

The body from a state of rest at uniformly accelerated motion with an acceleration of 1 m / s ^ 2 has passed 50 m. The speed of the body at the end of the path is equal to.

Initial data: a (the acceleration with which the body began to move) = 1 m / s ^ 2, S (the path that the body passed from rest) = 50 m.

Since the body began to move from a state of rest, the formula for calculating the path is:

S = V ^ 2 / 2a.

Let us express the speed of the body at the end of the path from the formula:

V = √ (2a * S).

Let’s do the calculation:

V = √ (2 * 1 * 50) = √100 = 10 m / s.

Answer: The speed of the body at the end of the path is 10 m / s.