The body has the shape of a rectangular parallelepiped with a length 4 m width 0.3 m height 25 cm determine

The body has the shape of a rectangular parallelepiped with a length 4 m width 0.3 m height 25 cm determine the Archimedean force acting on the body; the body is half immersed in clean water

a = 4 m.
d = 0.3 m.
h = 25 cm = 0.25 m.
g = 9.8 m / s ^ 2.
ρ = 1000 kg / m ^ 3.
Farkh -?
Archimedes’ force is determined by the formula: Farch = ρ * g * V1, where ρ is the density of the fluid in which the body is immersed, g is the acceleration of gravity, V1 is the volume of the part of the body immersed in the fluid.
The volume of a rectangular parallelepiped V is determined by the formula: V = a * d * h.
Since the body is half submerged in water, the volume of the submerged part will be V1 = V / 2.
Farch = ρ * g * a * d * h / 2.
Farch = 1000 kg / m ^ 3 * 9.8 m / s ^ 2 * 4 m * 0.3 m * 0.25 m / 2 = 1470 N.
Answer: the body is acted upon by the force of Archimedes Farkh = 1470 N.