The body is lifted vertically upward with an acceleration of 2 m / s ^ 2. Determine the body weight if a work
| March 9, 2021 | education
The body is lifted vertically upward with an acceleration of 2 m / s ^ 2. Determine the body weight if a work of 1.48 kJ was performed during the first five seconds.
To find the mass of the body being lifted, we will use the formula: A = F * S = m * (g + a) * a * t ^ 2/2, whence we express: m = 2A / ((g + a) * a * t ^ 2 ).
Constants and variables: A – perfect work (A = 1.48 kJ = 1.48 * 10 ^ 3 J); g – acceleration due to gravity (g ≈ 9.8 m / s2); a – acceleration during ascent (a = 2 m / s2); t is the duration of the rise (t = 5 s).
Calculation: m = 2A / ((g + a) * a * t ^ 2) = 2 * 1.48 * 10 ^ 3 / ((9.8 + 2) * 2 * 5 ^ 2) = 5 kg.
Answer: The mass of the body being lifted is 5 kilograms.
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