The body is moving equally slowly with an acceleration of 3 m / s ^ 2, having an initial speed of 13 m / s.

The body is moving equally slowly with an acceleration of 3 m / s ^ 2, having an initial speed of 13 m / s. The path traversed by the body is 24 m. What is the final velocity (m / s) of the body?

To find the final speed of a given body, we will use the formula: S = (Vn ^ 2 – Vk ^ 2) / 2a, whence we express: Vk = √ (Vn ^ 2 – S * 2a).

Variables: Vн – initial speed (Vн = 13 m / s); S – the path covered by the body (S = 24 m); a – acceleration (a = 3 m / s2).

Calculation: Vк = √ (Vн ^ 2 – S * 2a) = √ (13 ^ 2 – 24 * 2 * 3) = 5 m / s.

Answer: At the end of the equally slow motion, the body had a speed of 5 m / s.