The body is moving with an acceleration of 5 m / s2 on the path of 600m, the speed increased by 4 times, find the initial speed.

a = 5 m / s ^ 2.

S = 600 m.

V = 4 * V0.

V0 -?

With uniformly accelerated motion of the body, the traversed path S is determined by the formula: S = (V ^ 2 – V0 ^ 2) / 2 * a, where V, V0 are the final and initial speed of movement, a are the acceleration of the body.

Since the speed has increased 4 times V = 4 * V0, the formula will take the form: S = ((4 * V0) ^ 2 – V0 ^ 2) / 2 * a = (16 * V0 ^ 2 – V0 ^ 2) / 2 * a = 15 * V0 ^ 2/2 * a.

The formula for determining the initial speed will take the form: V0 = √ (2 * a * S / 15).

V0 = √ (2 * 5 m / s ^ 2 * 600 m / 15) = 20 m / s.

Answer: the initial velocity of the body was V0 = 20 m / s.