The body is thrown at an angle alpha to the horizon at a speed of 6 m / s. At what height will its kinetic energy

The body is thrown at an angle alpha to the horizon at a speed of 6 m / s. At what height will its kinetic energy be equal to half the potential? Consider that at the starting point its potential energy is zero.

Given: v = 6m / s, Eк = Еп / 2
Find: h =?
Decision:
Eк = Еп / 2
mv ^ 2/2 = mgh / 2
mv ^ 2 = mgh
v ^ 2 = gh
v = square root from gh
36 = 10h
h = 3.6 (m)
Answer: h = 3.6 m.