The body is thrown at an angle of 30 ° to the horizon. With what speed was the body thrown and what is the horizontal

| February 28, 2021 | education

The body is thrown at an angle of 30 ° to the horizon. With what speed was the body thrown and what is the horizontal range of its flight if it was in flight for 2 s? What is the maximum body height you can lift?

Task data: α (angle between the horizon and the vector of the speed of the thrown body) = 30º; t is the duration of the flight of the body (t = 2 s).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Initial speed of the throw: t = 2V0 * sinα / g, from where we express: V0 = t * g / (2 * sinα) = 2 * 10 / (2 * sin 30º) = 20 m / s.

2) Horizontal flight range: S = V0 ^ 2 * sin2α / g = 20 ^ 2 * sin (2 * 30º) / 10 = 34.64 m.

3) Maximum lifting height: hmax = V0 ^ 2 * sin2α / 2g = 20 ^ 2 * sin2 30º / (2 * 10) = 5 m.

Answer: The body was thrown at a speed of 20 m / s; rose to a maximum height of 5 m and flew 34.64 m.



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