The body is thrown at an angle of 45 degrees to the horizon with an initial speed of 100 m / s

The body is thrown at an angle of 45 degrees to the horizon with an initial speed of 100 m / s. determine the flight range and maximum lift height.

To find the range of the thrown body and the maximum height of its rise, we will use the formulas S = V0 ^ 2 * sin2α / g and hmax = V0 ^ 2 * sin2α / 2g.

The values of the variables: V0 – initial speed of the throw (V0 = 100 m / s); α (angle between the horizon and the velocity vector of the thrown body) = 45º.

Let’s calculate: a) flight range: S = V02 * sin2α / g = 100 ^ 2 * sin (2 * 45º) / 10 = 1000 m;

b) maximum lifting height: hmax = V02 * sin2α / 2g = 100 ^ 2 * sin2 45º / (2 * 10) = 250 m.

Answer: The abandoned body was able to rise to a height of 250 m, and its flight range is 1000 m (1 km).