The body is thrown at an angle of 60 ° to the horizon at a speed of 10 m / s.

The body is thrown at an angle of 60 ° to the horizon at a speed of 10 m / s. What is the horizontal component of the velocity at time t = 1 s.

To calculate the horizontal component of the speed of the thrown body, we will use the formula: Vx = V0x (horizontal speed does not depend on the moment in time) = V0 * cosα.

The values of the variables: V0 – initial speed of the throw (V0 = 10 m / s); α – angle of throw to the horizon (α = 60º).

Let’s calculate: Vx = V0 * cosα = 10 * cos 60º = 5 m / s.

Answer: The horizontal component of the speed of the thrown body is 5 m / s.




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