The body is thrown from a height H0 at an angle alpha to the horizon at a speed V

The body is thrown from a height H0 at an angle alpha to the horizon at a speed V, Flight time T. Flight range S, max. height H, at time t the body was at height h and at a distance L from the point of throw.

S = v² * sin (2α) / g => v = root (s * g / sin (2α));
v = v₀ = √ (151 m * 9.8 m / s² / sin (120 °)) = √ (151 m * 9.8 m / s² / 0.866) ≈ 41 m / s;
h = v₀ * sin (α) * t – g * t² / 2;
h = 41 m / s * sin (60 °) * 6 s – 9.8 m / s² * (6 s) ² / 2 ≈ 213 – 176 = 37 m;
T = 2 * v₀ * sin (α) / g = 2 * 41 m / s * sin (60 °) / 9.8 m / s² ≈ 7.2 s;
H = v₀² * sin² (α) / (2 * g) = (41 m / s) ² * 0.866² / (2 * 9.8 m / s²) ≈ 64 m.
Answer: v = 41 m / s; h = 37 m; T = 7.2 s; H = 64 m.