The body is thrown from a height of 3.2 m at a speed of 6 m / s at an angle to the horizon. Find the speed of the body when falling.
| February 13, 2021 | education
To find the speed of a thrown body at the moment of falling, we apply the law of conservation of energy: Ek0 + Ep0 = Ek and m * V0 ^ 2/2 + m * g * h0 = m * V ^ 2/2, whence we express: V2 = 2 * ( V0 ^ 2/2 + g * h0) and V = √ (2 * (V0 ^ 2/2 + g * h0)).
Constants and variables: V0 – throw speed (V0 = 6 m / s); g – acceleration due to gravity (g ≈ 10 m / s2); h0 – initial height (h0 = 3.2 m).
Calculation: V = √ (2 * (V0 ^ 2/2 + g * h0)) = √ (2 * (6 ^ 2/2 + 10 * 3.2)) = 10 m / s.
Answer: The thrown body must fall at a speed of 10 m / s.
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