Task data: Vg (horizontal throw speed) = 3 m / s; Sg (horizontal path distance) = 6 m.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
1) The duration of the fall: t = Sg / Vg = 6/3 = 2 s.
2) The height of the body at the moment of the horizontal throw: h = g * t ^ 2/2 = 10 * 2 ^ 2/2 = 20 m.
Answer: The horizontal throw of the body was made at a height of 20 m.
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