The body is thrown horizontally with a speed V0 = 10m / s what should be the height from which

The body is thrown horizontally with a speed V0 = 10m / s what should be the height from which the body was thrown so that it would be equal to the horizontal flight range.

In order for the height of the dropped body to be equal to the horizontal flight range, we will use the equality: Sg = Sv and Vg * t = g * t ^ 2/2.

Constants and variables: Vg – horizontal throw speed (Vg = 10 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Let’s find the duration of the fall: Vg * t = g * t ^ 2/2; Vg = g * t / 2, whence we express: t = 2 * Vg / g = 2 * 10/10 = 2 s.

Find the required height: h = Vg * t = 10 * 2 = 20 m.

Check: h = g * t ^ 2/2 = 10 * 2 ^ 2/2 = 20 m (correct).

Answer: The body must be thrown from a height of 20 m.