The body is thrown in a horizontal direction with a speed of Uo = 8 m / s.
The body is thrown in a horizontal direction with a speed of Uo = 8 m / s. Determine from what height h the body is thrown if the flight range S is equal to the height h. Answer h = 13 m
1) The distance that the body will pass horizontally (the horizontal speed is constant): S = Vо * t, where by the condition Vо = 8 m / s.
2) The height of the body falling (the body fell without initial velocity): h = a * t ^ 2/2, a = g = 9.8 m / s2.
3) Let’s calculate the time of the body falling under the condition that S = h.
Vo * t = g * t ^ 2/2.
Vo = g * t / 2.
2Vо = g * t and t = 2Vо / g.
t = 2 * 8 / 9.8 = 1.63 s.
4) Calculate the drop height:
h = Vo * t = 8 * 1.63 ≈ 13 m.
h = g * t ^ 2/2 = 10 * 1.63 ^ 2/2 ≈ 13 m.
Answer: The body was thrown from a height of 13 m.