The body is thrown vertically at a speed of 49 ms. At what height will its kinetic energy be equal to its potential?

To solve this problem, we find the total mechanical energy transferred to the body, it will be equal to the initial kinetic energy.
Eo = mV1 ^ 2/2
We denote the Ek-kinetic energy at the moment when it is equal to the potential
Then
En + Ek = Eo
Moreover, Ek = En, then:
2 * En = Eo
2 * m * g * h = m * V ^ 2/2
4 * m * g * h = m * V ^ 2
Let’s shorten by m:
4 * g * h = V ^ 2
h = V ^ 2 / 4g = 49 * 49 / (4 * 10) = 60m (approximately)
Answer: h = 60m