The body is thrown vertically downward at a speed of 5 m / s. Its speed for the fifth second of movement increases by?

To find the increase in the speed of the thrown body in the fifth second of the fall, we will use the formula: V (5) = V5 – V4 = (V0 + g * t5) – (V0 + g * t4) = g * (t5 – t4).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); t5 – the first time of the fall (t5 = 5 s); t4 – second fall time (t4 = 4 s).

Calculation: V (5) = g * (t5 – t4) = 10 * (5 – 4) = 10 m / s.

Answer: In the fifth second, the speed of the thrown body increased by 10 m / s.