The body is thrown vertically upward at a height of h = 10, the kinetic energy is equal to its potential

The body is thrown vertically upward at a height of h = 10, the kinetic energy is equal to its potential energy. if the air resistance is neglected, then the modulus of the initial velocity u0 of the body is.

To find the modulus of the initial velocity of the thrown body, we use the equality (the law of conservation of energy): Ek1 + En1 = 2En1 = Ek0 and 2 * m * g * h = m * V0 ^ 2/2, whence we express: V0 = √ (2 * 2 * g * h) = √ (4 * g * h).

Constants and variables: g – gravitational acceleration (g ≈ 10 m / s2); h is the height at which the energies were equal (h = 10 m).

Let’s calculate: V0 = √ (4 * g * h) = √ (4 * 10 * 10) = 20 m / s.

Answer: The module of the initial velocity of the body is 20 m / s.