The body is thrown vertically upward at a speed of 20 m / s. Calculate the height at which the speed

The body is thrown vertically upward at a speed of 20 m / s. Calculate the height at which the speed of the stone will be 2 times less.

To find the height at which the thrown stone will decrease its initial speed by 2 times, we use the formula: h = S = (V ^ 2 – Vn ^ 2) / 2a = (Vn ^ 2 – V ^ 2) / 2g.

Constants and variables: Vн – initial speed of the stone (Vн = 20 m / s); V is the required speed (V = 0.5Vn = 10 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: h = (Vn ^ 2 – V ^ 2) / 2g = (20 ^ 2 – 10 ^ 2) / (2 * 10) = 15 m.

Answer: The thrown stone reduced its initial speed by 2 times at a height of 15 m.