The body is thrown vertically upward at a speed of 40 meters per second. How long will the body’s

| July 6, 2021 | education

The body is thrown vertically upward at a speed of 40 meters per second. How long will the body’s speed (modulo) be 2 times less than at the beginning of the ascent?

It is known that the body is thrown vertically upward at a speed of Vо = 40 m / s. After some time t, the speed of the body (modulo) became 2 times less than at the beginning of the ascent, that is, V = 40 m / s: 2 = 20 m / s. To determine the time of the change in the speed of the body, we will use the formula that determines the acceleration: a = Δv: t, where the change in speed is Δv = (V – Vо) m / s; Δv = (20 – 40) m / s; Δv = – 20 m / s. Acceleration a = – g = – 9.8 m / (s • s). The minus sign appeared because the body is moving with equal slowness. Let us express from the formula t = Δv: a; t = – 20 m / s: (- 9.8 m / (s • s)); t ≈ 2 s.
Answer: after t ≈ 2 the speed of the body will decrease by 2 times.



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