The body is thrown vertically upward at a speed of 45 m / s. Determine the altitude and flight time.

Task data: V (the speed that the given body acquired at the moment of throwing) = 45 m / s.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Maximum lifting height: a) S = V ^ 2 / 2а = V ^ 2 / 2g = 45 ^ 2 / (2 * 10) = 101.25 m;

b) En = Ek and m * g * h = m * V ^ 2/2, whence we express: h = V ^ 2 / 2g = 101.25 m.

2) Flight time: t = t1 (rise) + t2 (fall) = 2t1 = 2 * V / a = 2 * V / g = 2 * 45/10 = 9 s.

Answer: The given body was able to rise to a height of 101.25 m; his flight lasted 9 seconds.