The body is thrown vertically upward at a speed of v0 = 15 m / s. Determine at what height h the potential energy

The body is thrown vertically upward at a speed of v0 = 15 m / s. Determine at what height h the potential energy Ep of the body is n = 1.6 times greater than the kinetic Eк. Disregard air resistance.

To find the height at which a body thrown vertically should be, we apply the law of conservation of energy: En1 + Ek1 = En1 + Ep1 / 1.6 = En1 + 0.625En1 = 1.625En1 = Ek0 and 1.625 * m * g * hx = m * V0 ^ 2/2, whence we express: hx = V0 ^ 2 / (2 * 1.625 * g) = V0 ^ 2 / (3.25 * g).

Constants and variables: V0 – speed of throwing upwards (V0 = 15 m / s); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: hx = V0 ^ 2 / (3.25 * g) = 15 ^ 2 / (3.25 * 10) ≈ 6.9 m.

Answer: The abandoned body will be at a height of 6.9 m.