The body is thrown vertically upward with an initial speed of 20 m / s. At what height will its kinetic energy

The body is thrown vertically upward with an initial speed of 20 m / s. At what height will its kinetic energy be equal to its potential? The potential energy on the Earth’s surface is zero.

According to the law of conservation of energy:
Eк1 + Eп1 = Eк2 + Eп2, where Eк1 and Eп1 – energy at the moment of throw; Eк2 and Eп2 – energy at the moment of equality of En and Ek.
At the beginning of the throw: h = 0, Ep1 = 0.
At the moment of reaching the maximum height: Eк2 = Ep2.
Eк1 = Eк1 + Ep2 = 2Eп2.
Eк1 = (m * V ^ 2) / 2, m-body mass, V-body speed at the moment of throw (V = 20 m / s).
Ep2 = m * g * h, g-free fall acceleration (g = 10m / s ^ 2), h-height (m).
(m * V ^ 2) / 2 = 2m * g * h;
h = (V ^ 2) / (2 * g) = (20 ^ 2) / (4 * 10) = 400/40 = 10 m.
Answer: The kinetic energy is equal to the potential energy at a height of 10 m.