The body is thrown vertically upwards from a height of h = 3 m above the Earth’s surface; it rises H-7 m above the drop point

The body is thrown vertically upwards from a height of h = 3 m above the Earth’s surface; it rises H-7 m above the drop point, then falls to the ground. Find the module of movement and the path traveled by the body in this movement.

h = 3 m.
H = 7 m.
S -?
L -?
The movement of the body S is called the vector connecting the initial and final position of the body.
Since the body began to move from a height of h = 3 m and finished movement on the earth’s surface when the height is 0. Moving the body S = h = 3 m.
The path L traveled by the body is the distance that the body has traveled during movement.
The body began to move from a height of h = 3 m and, having flown a distance of H = 7 m, stopped at a height of h + H = 3 m + 7 m = – 10 m. From a height of 10 m, it fell to the ground.
Upward, the body passed a path of 7 m and downward a path of 10 m, the entire path L = 7 m + 10 m = 17 m.
Answer: body displacement S = 3 m, distance traveled L = 17 m.