The body m = 1 kg moves in a straight line, according to the equation: s = 3t + 5t ^ 2 – t3 (m).

The body m = 1 kg moves in a straight line, according to the equation: s = 3t + 5t ^ 2 – t3 (m). What force is acting on the body at the end of the first second of movement?

Problem data: m (mass of the considered body) = 1 kg; the equation of motion is S = 3t + 5t ^ 2 – t ^ 3.

1) The equation by which the acceleration of the body changes: a = S ” = (3t + 5t ^ 2 – t ^ 3) ” = (3 * 1 – 5 * 2 * t – 3 * t ^ 2) ‘= ( 3 – 10t – 3t ^ 2) ‘= 3 – 10 * 1 – 3 * 2 * t = 10 – 6t.

2) Acceleration of the body at the end of the first second of movement: a (1) = 10 – 6 * 1 = 4 m / s2.

3) The force that acts on the body in question: F = m * a = 1 * 4 = 4 N.

Answer: At the end of the first second of movement, a force of 4 N will act on the body.