The body moves according to the law x = 5-3t + 8t2 (m). Find the body acceleration module.

We define the acceleration of the body by taking the double derivative (second-order derivative) from the function:
x = S = 5 – 3t + 8t².
x ‘= V = (-3t + 8t²)’ = -3 * 1 + 8 * 2t = -3 + 16t.
x ” = S ” = V ‘= a = t’ = (-3 + 16t) ‘= 16 * 1 = 16 m / s².
Answer: The body’s acceleration modulus is 16 m / s².



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