The body moves along the Ox axis with constant acceleration. The projection onto the Ox axis

| August 13, 2021 | education

The body moves along the Ox axis with constant acceleration. The projection onto the Ox axis of the final velocity of the body Vx = 3.0 m / s, the projection of the acceleration ax = -2.0 m / s2. Determine the projection of the initial speed of movement of the body if the projection of its movement during the movement is rx = 4.0 m.

To find the desired projection of the initial velocity of motion of the body under consideration, we apply the following formula: S = rx = (Vx ^ 2 – Vn ^ 2) / 2ax, whence we express: Vn = √ (Vx ^ 2 – rx * 2ax).

Variable values: Vx – projection of the final speed (Vx = 3 m / s); rx – projection of displacement (rx = 4 m); ax – projection of acceleration (ax = -2 m / s2).

Let’s perform the calculation: Vн = √ (Vx ^ 2 – rx * 2ax) = √ (3 ^ 2 – 4 * 2 * (-2)) = 5 m / s.

Answer: The desired projection of the initial velocity is 5 m / s.



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