The body moves equally noticeably with an acceleration of 1m / s ^ 2 start speed 4m / s which

The body moves equally noticeably with an acceleration of 1m / s ^ 2 start speed 4m / s which way the body will pass the moment when its old speed is 2m / s.

To calculate the path traveled by the body before reaching the required speed, we apply the formula: S = (Vn ^ 2 – Vk ^ 2) / 2a.

Variable values: Vн – initial speed (Vн = 4 m / s); Vк – required speed (Vк = 2 m / s); a – constant acceleration (a = 1 m / s2).

Calculation: S = (Vn ^ 2 – Vk ^ 2) / 2a = (4 ^ 2 – 2 ^ 2) / (2 * 1) = 6 m.

Answer: A given body will reach a speed of 2 m / s after passing a path of 6 m.