The body moves in a circle at a constant speed of 10 m / s, making a revolution in 62.7 s.

The body moves in a circle at a constant speed of 10 m / s, making a revolution in 62.7 s. find the centripetal acceleration.

Given:

v = 10 meters per second – the speed of a body moving in a circle;

t = 62.7 seconds – the time interval during which the body makes 1 revolution;

pi = 3.14 is a geometric constant (Pythagoras number).

It is required to determine a (q) – the centripetal acceleration of the body.

Let’s find the length of the circle along which the body moves:

L = v * t = 10 * 62.7 = 627 meters.

Then the radius of this circle will be equal to:

r = L / (2 * pi) = 627 / (2 * 3.14) = 627 / 6.28 = 99.8 meters (the result is rounded to one decimal place).

The centripetal acceleration will be equal to:

a (q) = v ^ 2 / r = 10 ^ 2 / 99.8 = 100 / 99.8 = 1 m / s2 (the result is rounded to integers).

Answer: the centripetal acceleration of the body is 1 m / s2.