The body moves uniformly from the spot. In the first 2 seconds, it covers a path of 20 cm.

The body moves uniformly from the spot. In the first 2 seconds, it covers a path of 20 cm. What path did the body cover in the second second?

To find the path traversed by the body in question in the second second of accelerated motion, we apply the formula: S (2) = S2 – S1 = S2 – a * t1 ^ 2/2 = S2 – (2S2 / t2 ^ 2) * t1 ^ 2/2 = S2 – S2 * t1 ^ 2 / t2 ^ 2 = S2 * (1 – t1 ^ 2 / t2 ^ 2).

Values of variables: S2 – path in 2 seconds (S2 = 20 cm = 0.2 m); t1 – first time (t1 = 1 s); t2 – total time (t2 = 2 s).

Calculation: S (2) = S2 * (1 – t1 ^ 2 / t2 ^ 2) = 0.2 * (1 – 1 ^ 2/2 ^ 2) = 0.2 * 0.75 = 0.15 m.

Answer: In the second second, the body under consideration traveled a path of 0.15 m.