The body moves with an acceleration of 2m / s2, what path will it cover in 10 s if the initial speed is 4m / s?

To calculate the path traversed by a given body in 10 seconds, we will use the formula: S = Vn * t + a * t ^ 2/2.

Variables: Vн – initial speed (Vн = 4 m / s); t is the duration of the movement (t = 10 s); a – acceleration (a = 2 m / s2).

Calculation: S = Vн * t + a * t ^ 2/2 = 4 * 10 + 2 * 10 ^ 2/2 = 140 m.

Answer: In 10 seconds of movement, a given body will cover a path of 140 meters.