The body moves with equal slowness with an acceleration of 1m / s2 and an initial speed of 4m / s.

The body moves with equal slowness with an acceleration of 1m / s2 and an initial speed of 4m / s. What path will the body travel to the moment when its speed becomes equal to 2m / s?

Initial data: the movement is equally slow; a (acceleration) = -1 m / s2; V1 (initial velocity of the considered body) = 4 m / s; V2 (the speed that the body must reach) = 2 m / s.

The path that the body under consideration will have time to pass before reaching a speed of 2 m / s is calculated by the formula: S = (V2 ^ 2 – V1 ^ 2) / 2a.

Let’s perform the calculation: S = (2 ^ 2 – 4 ^ 2) / (2 * (-1)) = 6 m.

Answer: Before reaching a speed of 2 m / s, the body will have time to walk 6 meters.