The body, moving at a speed of 36 km / h, stopped after passing 200m.
| September 8, 2021 | education
The body, moving at a speed of 36 km / h, stopped after passing 200m. Find the braking time if the coefficient of friction is 0.2.
Initial data: V0 (initial body speed) = 36 km / h = 10 m / s; S (the path that the body traveled during braking) = 200 m; μ (coefficient of friction) = 0.2.
Constants: g (acceleration due to gravity) = 10 m / s ^ 2.
1) Determine the acceleration with which the body was moving:
m * a = -Ftr. = -μ * N (support reaction) = -μ * m * g.
a = -μ * g = -0.2 * 10 = -2 m / s ^ 2.
2) Let’s calculate the braking time of the body:
V = V0 + a * t; a * t = -V0.
t = -V0 / a = -10 / (-2) = 5 s.
Answer: The body deceleration time was 5 seconds.
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