The body, moving equally slowly, by the end of the second second after the start of time

The body, moving equally slowly, by the end of the second second after the start of time, had a speed of 2 m / s and traveled a distance of 10 m. Determine the magnitude of the acceleration.

Data: t (considered duration of movement) = 2 s; Vk (achieved speed) = 2 m / s; S (distance traveled) = 10 m.

1) Let’s find the initial speed of a given body: S = (Vк + Vн) * t / 2, from where we express: Vн = 2S / t – Vк = 2 * 10/2 – 2 = 8 m / s.

2) Calculate the amount of acceleration: a = (Vk – Vn) / t = (2 – 8) / 2 = -3 m / s2.

Check: S = Vn * t + a * t ^ 2/2 = 8 * 2 + (-3) * 2 ^ 2/2 = 10 m (correct).

Answer: The acceleration was -3 m / s2.