The body, moving from a state of rest with an acceleration of 6 m / s2, reached a speed of 36 m / s

The body, moving from a state of rest with an acceleration of 6 m / s2, reached a speed of 36 m / s, and then stopped after 5 s. Determine the path traveled by the body during the entire movement.

Given:

a = 6 m / s ^ 2 – initial acceleration of the body;

v = 36 m / s – body speed before braking;

t = 5 seconds – the time interval from the start of braking to the stop of the body.

It is required to determine the total distance traveled S (meter) by the body.

S = S acceleration + S deceleration.

Acceleration = a * t1 ^ 2/2 = a * (v / a) ^ 2/2 = v ^ 2 / (2 * a) = 36 ^ 2 / (2 * 6) =

= 1296/12 = 108 meters.

Braking = v * t – a * t ^ 2/2 = v * t – v * t / 2 = v * t / 2 = 36 * 5/2 = 180/2 =

= 90 meters.

S = 108 + 90 = 198 meters.

Answer: the total distance traveled is 198 meters.