The body, moving in a straight line with an acceleration of 5 m / s2, reached a speed of 30 m / s
| February 23, 2021 | education
The body, moving in a straight line with an acceleration of 5 m / s2, reached a speed of 30 m / s, and then, moving equally slowly, stopped after 10 s. Determine the path traveled by the body.
To calculate the total path that a given body should have traveled, we will use the formula (the initial speed is taken to be zero): S = S1 + S2 = V12 / 2a + V1 * t / 2.
The values of the variables: V1 – the speed reached by the body in the first section (V1 = 30 m / s); a – acceleration in the first section (a = 5 m / s2); t – duration of uniformly slowed motion (t = 10 s).
Calculation: S = V1 ^ 2 / 2a + V1 * t / 2 = 30 ^ 2 / (2 * 5) + 30 * 10/2 = 240 m.
Answer: The total path of a given body is 240 meters.
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