The body, moving uniformly accelerated from a state of rest, traveled 4.8 m in 4 s.
| August 8, 2021 | education
The body, moving uniformly accelerated from a state of rest, traveled 4.8 m in 4 s. What way did it travel in the fourth second?
V0 = 0 m / s.
t = 4 s.
S = 4.8 m.
t3 = 3 s.
S4 -?
The distance traveled by the body in the fourth second S4 will be the difference: the distance traveled in four seconds S and the distance traveled in three seconds S3: S4 = S – S3.
S3 = V0 * t3, + a * t3 ^ 2/2.
Since V0 = 0 m / s, then S3 = a * t3 ^ 2/2.
The acceleration of the body a is found from the formula: S = a * t ^ 2/2.
a = 2 * S / t ^ 2.
S3 = 2 * S * t3 ^ 2/2 * t ^ 2 = S * t3 ^ 2 / t ^ 2.
S3 = 4.8 m * (3 s) ^ 2 / (4 s) ^ 2 = 2.7 m.
S4 = 4.8 m – 2.7 m = 2.1 m.
Answer: the body passed the distance S4 = 2.1 m in the fourth second.
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