The body, moving uniformly accelerated in the fifth second, covered a distance equal to 18m.

The body, moving uniformly accelerated in the fifth second, covered a distance equal to 18m. Find the path of the body in the initial 10 seconds.

These tasks: S (5) – the path that the body covered in the fifth second (S (5) = 18 m); t – initial time of movement (t = 10 s).

1) Find the constant acceleration: S (5) = S5 – S4 = a * t5 ^ 2/2 – a * t4 ^ 2/2 = a / 2 * (t5 ^ 2 – * t4 ^ 2), whence we express: a = S (5) * 2 / (t5 ^ 2 – * t4 ^ 2) = 18 * 2 / (5 ^ 2 – 4 ^ 2) = 4 m / s2.

2) Calculate the path for the initial 10 seconds: S = a * t ^ 2/2 = 4 * 10 ^ 2/2 = 200 m.

Answer: In the initial 10 seconds, a given body has covered a path of 200 meters.