The body, moving uniformly slower with an acceleration of 2.7 m / s2, covered a path of 500 m

The body, moving uniformly slower with an acceleration of 2.7 m / s2, covered a path of 500 meters. Find the initial speed if the body was becoming.

These tasks: uniform slow motion; a (acceleration modulus) = 2.7 m / s2; S (path traversed by a given body) = 500 m; the body has stopped (V2 (final speed) = 0 m / s).

We express the initial speed of a given body from the formula: S = (V12 – V22) / 2a, whence V12 – 0 = S * 2a and V1 = √ (S * 2a).

Let’s make a calculation: V1 = √ (500 * 2 * 2.7) = √2700 = 51.96 m / s.

Answer: The initial speed of the given body was 51.96 m / s.