The body of free fall fell for 2 seconds during this time, how long will it fly?

Given:

t = 2 seconds – time of body fall;

g = 9.8 m / s2 – acceleration of gravity.

It is required to determine S (meter) – the distance that the body will fly in time t.

According to the condition of the problem, the body fell freely, that is, without initial velocity (v0 = 0). Then:

S = v0 * t + g * t ^ 2/2 = 0 * 2 + 9.8 * 2 ^ 2/2 = 0 + 9.8 * 4/2 = 39.2 / 2 = 19.6 meters.

Answer: in 2 seconds of free fall, the body will fly a path equal to 19.6 meters.



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