The body on the track section S = 600m, develops a traction force F = 147kN. The speed of a body of mass

| April 22, 2021 | education

The body on the track section S = 600m, develops a traction force F = 147kN. The speed of a body of mass m = 1000t increases from V0 = 36 km / h to V1 = 54 km / h. Find the force of resistance to movement f.

To find the value of the resistance force to the movement of a given body, we project all the forces on the horizontal axis: m * a = Ftyag – Fcopr, whence Fcopr = Ftyag – m * a = Ftyag – m * (V1 ^ 2 – V0 ^ 2) / 2S.

Values of variables: Ftyag – the body’s traction force (Ftyag = 147 kN = 147 * 10 ^ 3 N); m – mass (m = 1000 t = 1 * 106 kg); V1 is the final speed of the body (V1 = 54 km / h = 15 m / s); V0 – initial speed (V0 = 36 km / h = 10 m / s); S – distance traveled (S = 600 m).

Calculation: Fcopr = Ftyag – m * ((V1 ^ 2 – V0 ^ 2) / 2S) = 147 * 10 ^ 3 – 1 * 10 ^ 6 * (152 – 10 ^ 2) / (2 * 600) = 42, 83 * 10 ^ 3 H = 42.83 kN.

Answer: The force of resistance to movement is 42.83 kN.



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