The body passed 3 km in the horizontal direction, then turned at an angle of 90 degrees and passed another 4 km.

The body passed 3 km in the horizontal direction, then turned at an angle of 90 degrees and passed another 4 km. How many times are the path and movement of the body different?

Given:

S1 = 3 km – the path of the body in the horizontal direction;

S2 = 4 km – body path after turning 90 degrees.

It is required to find the ratio of the path and displacement of the body S / L.

First, let’s find the full path traveled:

S = S1 + S2 = 3 + 4 = 7 km.

Next, let’s find the displacement:

L = √ (S1 ^ 2 + S2 ^ 2) = √ (9 + 16) = √ (25) = 5.

S / L = 7/5 = 1.4

Answer: the path is 1.4 times greater than the displacement.