The body stretches the spring under the force of 40N. How much the spring will stretch if the stiffness coefficient is 8n / m.

F = 40 Newton – the force under which the spring is stretched;

k = 8 Newton / meter – coefficient of spring stiffness.

It is required to determine dx (meter) – the amount of spring elongation under the action of the force F.

To determine the amount of spring elongation, you must use the following formula (Hooke’s law):

F = k * dx, from here we find:

dx = F / k;

dx = 40/8 = 20/4 = 5 meters.

Answer: the spring will stretch 5 meters.