The body, the initial velocity of which is V1 = 10m / s, begins to move with a certain constant acceleration

The body, the initial velocity of which is V1 = 10m / s, begins to move with a certain constant acceleration and, during the time t = 5 s, acquires the velocity V2 = 30m / s. The path traversed by the body during this time is …

To calculate the distance that a given body has traveled in 5 seconds of acceleration, we apply the formula: S = 0.5 * (V2 + V1) * t.

Variables: V2 – acquired (final) speed (V2 = 30 m / s); V1 – initial speed (V1 = 10 m / s); t – body time in motion (t = 5 s).

Calculation: S = 0.5 * (V2 + V1) * t / 2 = 0.5 * (30 + 10) * 5 = 100 m.

Answer: C) in 5 seconds of acceleration, a given body covered a distance of 100 m.



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