The body, thrown vertically upward, rose to a height of 20 m and fell into a shaft 15 m deep.
| August 15, 2021 | education
The body, thrown vertically upward, rose to a height of 20 m and fell into a shaft 15 m deep. What is the distance traveled and the modulus of movement of the body.
To find the path traversed by the thrown body and its movement, we will use the formulas: S = h1 + h2 = h1 + (h1 + h3) = 2h1 + h3 and | S | = | S2 | – | S1 | = h2 – h1 = h1 + h3 – h1 = h3.
Variable values: h1 – lifting height (h1 = 20 m); h2 – the height of the fall from the upper lifting point to the bottom of the mine; h3 – shaft depth (h3 = 15 m).
Calculation: a) distance traveled: S = 2h1 + h3 = 2 * 20 + 15 = 55 m.
b) moving: | S | = h3 = 15 m.
Answer: The body traveled a path equal to 55 m, its displacement was 15 m.
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